Columbus Easter Egg



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After some rearranging, we can see that areas of the parts are: Part A = (π*12)/2 = π/2; Parts B = (π*22)/8 = π/2, i.e., Part A = Part B. Part D > Part C. Thus, the total area of the light parts is greater than the total area of the dark parts.

Posted: April 8, 2012
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